Sunday, January 15, 2012

Monty Hall Problem

Source: Various(Movies e.g. 21, Maths courses, books on basic probability)

Problem: Its Monty hall, also used in movie ‘21’,when Kevin spacey asks
Jim Sturgess in form of game show host problem.


You are on a game show and there are three doors. The presenter tells
 you that behind one of doors there is a car and behind the other two are
 goats. If you pick the car you win it. After you have picked a door the
 presenter opens a different door with a goat behind it, he then gives you
the chance to change your choice to what door you open. What should you do?

1 comment:

  1. Initially all the doors have the same probabilities i.e. 1/3,1/3 and 1/3
    The probability that your choice is correct is 1/3 and other way round is 2/3.
    But you don’t know whether your choice is correct or not.

    Now the game show host revealed the goat behind one of the door, so the 2/3 for the 2 doors becomes 2/3 probability for a single door, which is obviously greater then 1/3.
    So if you change your choice your chance of winning goes upto 66.67 %

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